Question 1193126
It is a complex function (b^2-4ac=-3)
f(i)=I^2-3i+3=2-3i
f(-1)=7
f(-1+i)=1-2i+I^2+3-3i+3=6-5i
f(2+i)=4+4i+I^2-6-3i+3=i