Question 1193021
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Technically, it is a polynomial of degree 2, so it has 2 zeros.<br>
If you mean real zeros, then....<br>
(1) Convert the equation to standard form {{{ax^2+bx+c=0}}} and look at the discriminant {{{b^2-4ac}}}.  There are 2 zeros if the discriminant is positive, 1 zero if it is 0, and no (real) zeros if it is negative.<br>
(2) The equation as given is in vertex form.  The vertex is (-1,-6) and the parabola opens upward, so there are 2 real zeros.<br>