Question 1192990
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if the function x^3 + 2x^2 - ax - 8 is evenly divisible by (x+2), find the value of a
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<pre>
According to the Remainder theorem, the number -2 is the root of the polynomial.


So, substitute this value of -2 into the polynomial.


It will give you an equation for the unknown coefficient "a"


    (-2)^3 + 2*(-2)^2 - a*(-2) - 8 = 0,

or

    -8 + 2*4 + 2a - 8 = 0,

    2a = 8

     a = 8/2 = 4.


<U>ANSWER</U>.  a = 4.
</pre>

Solved.