<PRE><B>Question 1192736</B>
&lt;pre&gt;

Lets look at the dice first:  There are 36 possible outcomes, of these we have this table for the sums:

Sum   # ways

 2     1
 3     2
 4     3
 5     4
 6     5    (1+5, 2+4, 3+3, 4+2, 5+1,  where we consider first die + second die)
 7     6
 8     5
 9     4
 10    3
 11    2
 12    1
     ----
      36       

So a sum of 6 will have probability 5/36   (this should make sense!)


Now look at the two coin flips:

 HH
 HT        
 TH
 TT   

A head and tail can be tossed with probability  2/4 = 1/2

Since these events are independent, we multiply:  (5/36)*(1/2) = {{{ highlight( 5/72)  }}}</PRE>