<PRE><B>Question 1192865</B>
&lt;br&gt;
A standard formal algebraic setup for solving the problem....&lt;br&gt;
x = # of adult tickets
600-x = # of child tickets&lt;br&gt;
The total cost of the tickets was $4400:&lt;br&gt;
{{{8(x)+6(600-x)=4400}}}&lt;br&gt;
That equation is easily solved using basic algebra:&lt;br&gt;
{{{8x+3600-6x=4400}}}
{{{2x=800}}}
{{{x=400}}}&lt;br&gt;
x=400 adult tickets; so 600-x=200 children tickets.&lt;br&gt;
ANSWER: 200 child tickets&lt;br&gt;
If formal algebra is not required, here is a quick solution method using logical reasoning and simple mental arithmetic.&lt;br&gt;
600 adult tickets would have cost $4800; 600 child tickets would have cost $3600.
The actual total, $4400, is 2/3 of the way from $3600 to $4800; therefore, 2/3 of the tickets were adult tickets.&lt;br&gt;
So 2/3 of 600 = 400 adult tickets, and 1/3 of 600 = 200 child tickets.&lt;br&gt;
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