Question 1192873


 the area is {{{A=(1/2)b*h}}} where {{{b}}} is the base and {{{h}}} is the height

if the base of a triangle is {{{4}}} inches more than{{{ 4}}} times the height, we have
{{{b=4h+4}}}
and if the area is {{{40in^2}}}, we have

 {{{40=(1/2)(4h+4)*h}}}
{{{80=(4h+4)*h}}}
{{{80=4h^2+4h}}}......simplify
{{{20=h^2+h}}}
{{{0=h^2+h-20}}}
{{{0 = (h - 4) (h + 5)}}}

we need only positive solution: {{{h=4}}}

then {{{b=4*4+4}}}->{{{b=20}}}