Question 1192828
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Case 1: Using only 2,4,6,8

There are P(4,4) = (4)(3)(2)(1) = 4! = 24 ways to arrange them.

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Case 2: Using 10, and 2 others digits from 2,4,6,8

There are 3 basic ways for case 2: 
10 _ _,   _ 10 _, and _ _ 10

For each of those 3, there are P(4,2) = (4)(3) = 12 ways to arrange
two others in the 2 blanks.

So that's (3)(12) = 36 ways.

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Case 3: Using 12, and 2 others digits from 2,4,6,8.

That's the same answer as Case 2, also 36 ways.

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Case 4:  Using both 10 and 12.

Only 2 ways, 1012 and 1210.

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Total for all 4 cases: 24+36+36+2 = 98 ways.

Edwin</pre>