Question 1192789
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{{{g(x)=ab^x}}}<br>
Knowing g(0), we can find the value of a quickly.<br>
{{{g(0)=ab^0=a(1)=a=13}}}<br>
So a=13; the equation is {{{g(x)=13b^x}}}.  Use that in the equation for the other given point to find b.<br>
{{{g(-2)=13(b^(-2))=13/6}}}
{{{b^(-2)=1/6}}}
{{{b^2=6}}}
{{{b=sqrt(6)}}}<br>
The exponential function is {{{g(x)=13((sqrt(6))^x)}}}<br>