Question 1192780
<font color=black size=3>
Given Table
<table border = "1" cellpadding = "5"><tr><td>X</td><td>-2</td><td>-1</td><td>0</td><td>1</td><td>2</td></tr><tr><td>P(X)</td><td>1/8</td><td>2/8</td><td>2/8</td><td>2/8</td><td>1/8</td></tr></table>


The notation P(X ≤ 2) means "The probability X ≤ 2 occurs"
This means X = 2 or X < 2.
As the table shows, the largest item is X = 2 itself, meaning that X ≤ 2 encompasses all possible outcomes. Therefore, we have 100% probability that X ≤ 2 happens.
We write P(X ≤ 2) = <font color=red>1</font>
Note that all the fractions add to: 1/8+2/8+2/8+2/8+1/8 = (1+2+2+2+1)/8 = 8/8 = 1.


P(X > -2)  = <font color=red>7/8</font> because P(X = -2) = 1/8, so being larger than -2 will have a probability of 1 - 1/8 = 7/8.
Or you could add up all the P(x) values for X = -1 all the way up to X = 2.


P(-1 ≤ X ≤ 1) = P(-1) + P(0) + P(1)
P(-1 ≤ X ≤ 1) = 2/8 + 2/8 + 2/8
P(-1 ≤ X ≤ 1) = (2+2+2)/8
P(-1 ≤ X ≤ 1) = 6/8
P(-1 ≤ X ≤ 1) = <font color=red>3/4</font>


P(X ≤ -1) = P(-2) + P(-1)
P(X ≤ -1) = 1/8 + 2/8
P(X ≤ -1) = 3/8
P(X ≤ -1 or X = 2) = P(X ≤ -1) + P(X = 2)
P(X ≤ -1 or X = 2) = 3/8 + 1/8
P(X ≤ -1 or X = 2) = 4/8
P(X ≤ -1 or X = 2) = <font color=red>1/2</font>


This is a discrete probability distribution with X only able to take on the values from the set {-2, -1, 0, 1, 2}
Something like X = 1.15 is not possible. 
Saying X ≤ 1.15 is the same as X ≤ 1 because X = 1 satisfies the requirements that X = 1.15 or X < 1.15.
So P(X ≤ 1.15) = P(X ≤ 1) = <font color=red>7/8</font> which can be found by adding every P(X) value from x = -2 on up to x = 1; or take the shortcut 1 - P(2) = 1 - 1/8 = 7/8.


P(X ≤ 2.2) = P(X ≤ 2) = <font color=red>1</font> for similar reasoning as mentioned earlier.


P(-1.1 < X ≤ 1) = P(-1 < X ≤ 1) 
P(-1.1 < X ≤ 1) = <font color=red>3/4</font> also found earlier



P(X > 0) = P(X ≥ 1)
P(X > 0) = P(1) + P(2)
P(X > 0) = 2/8 + 1/8
P(X > 0) = <font color=red>3/8</font>


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Answers:


Part 1
(a)P(X ≤ 2) = <font color=red>1</font>
(b)P(X > -2) = <font color=red>7/8</font>
(c)P(-1 ≤ X ≤ 1) = <font color=red>3/4</font>
(d)P(X ≤ -1 or X=2) = <font color=red>1/2</font>


Part 2
(a)P(X ≤ 1.15) = <font color=red>7/8</font>
(b)P(X ≤ 2.2) = <font color=red>1</font>
(c)P(-1.1 < X ≤ 1) = <font color=red>3/4</font>
(d)P(X > 0) = <font color=red>3/8</font>
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