Question 1192690
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The total number of possible outcomes when rolling two ordinary dice is 6*6=36.<br>
6 of those outcomes have a sum of 7: 1+6, 2+5, 3+4, 4+3, 5+2, and 6+1.
2 of those outcomes have a sum of 11: 5+6 and 6+5.<br>
The number of ways of getting a sum of 7 or 11 is 6+2=8; the total number of possible outcomes is 36.<br>
ANSWER: P(7 or 11) = 8/36 = 2/9<br>