Question 1192671
expected value=0.73*1717=1253.41
variance=np(1-p)=1253.41*0.27=338.42
sd=sqrt(V)=18.40
for 1251 z=(1250.5-1253.4)/18.40, using the continuity continuation factor=-0.16
for 1271 z=(1271.5-1253.4)/18.40, =0.98
probability of z between those two values is 
=0.4000
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> 1271 is z= (1271.5-1253.4)/18.4=0.98
that probability is 0.1635