Question 1192664
By what like amount does the length and width of a 6" by 4" rectangle need to be increased for it's area to be doubled
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6*4 = 24
(6+x)*(4+x) = 48
x^2 + 10x + 24 = 48
x^2 + 10x - 24 = 0
(x+12)*(x-2) = 0
x = 2
---> 8 by 6
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PS  it's = it is