Question 1192548
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The foci are (1,5) and (3,5); so the center is (2,5), and the distance from the center to each focus, c, is 1.<br>
The eccentricity 0.25=1/4 is c/a, where a is the semi-major axis; so a=4.<br>
c^2=a^2-b^2 where b is the semi-minor axis, so b is sqrt(15).<br>
The major axis is horizontal, so the equation is<br>
{{{(x-h)^2/a^2+(y-k)^2/b^2=1}}}<br>
{{{(x-2)^2/16+(y-5)^2/15=1}}}<br>