Question 1192552
y=(x+a)^2
0=(4+a)^2; a=-4
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y=(x-4)^2+b the vertex is (-a, b) or (4, -9)
b=-9
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0=(x-4)^2-9=x^2-8x+7=(x-1)(x-7)
p and q are 1 and 7 or 7 and 1
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r=(0-4)^2-9=7
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{{{graph(300,300,-10,10,-10,10,(x-4)^2,(x-4)^2-9)}}}