Question 113291

{{{4x^2 + 28x + 49 = 0}}}

You have:

{{{a = 4}}}

{{{b = 28}}}

{{{c = 49}}}

Use the square root formula and find roots:

{{{x[1,2]=(-b +- sqrt (b^2 -4*a*c )) / (2*a)}}}

{{{x[1,2]=(-28 +- sqrt (28^2 -4*4*49 )) / (2*4)}}}


{{{x[1,2]=(-28 +- sqrt (784 - 784)) / 8}}}


{{{x[1,2]=(-28 +- sqrt (0)) / 8}}}

{{{x[1]=(-28 +- 0)/8}}}………..there is only one solution

{{{x[1] = - 3.5}}}