Question 113291
You are given the area of the square as:
{{{A = 4x^2+28x+49}}} and, as you know, the area of a square is {{{A = s^2}}} where s is the length of one side of the square, so...
{{{s^2 = 4x^2+28x+49}}}
Let's factor the trinomial to see if it's a perfect square:
{{{4x^2+28x+49 = (2x+7)(2x+7)}}}={{{(2x+7)^2}}} it is a perfect square, so...
{{{s^2 = (2x+7)^2}}} Now take the square root of both sides.
{{{s = (2x+7)}}} and this is the length of one side of the square in terms of x.