Question 1192497
Find the derivative of x^2+3x-1/(4x)^4/5
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f(x) = (x^2+3x-1)*(4x)^-4/5
f'(x) = {{{(2x+3)*(4x)^(-0.8) + (x^2+3x-1)*(-4/5)*(4x)^(-1.8)*4}}}