Question 1192495
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Two buses leave towns 484 kilometers apart at the same time and travel toward each other. 
One bus travels 18 km/h faster than the other. If they meet in 2 hours, what is the rate of each bus.
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<pre>
Let x be the average rate of the slower bus, in kilometers per hour.

Then the rate of the other base is (x+18) km/h.


One bus' traveled  distance is  2x kilometers.

The other bus' traveled distance is 2*(x+18) kilometers.


The total distance equation is

    2x + 2*(x+18) = 484  kilometers.


Simplify and find x

    2x + 2x + 36 = 484

       4x        = 484 - 36

       4x        =    448

        x        =    448/4 = 112.


<U>ANSWER</U>.  The slower bus rate is  112 km/h.  The faster bus rate is  112+18 = 130 km/h.


<U>CHECK</U>.   112*2 + 130*2 = 484 kilometers, the total distance.   ! Precisely correct !
</pre>

Solved.


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For simple Travel & Distance problems, &nbsp;see introductory lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

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