Question 1192379
<br>
P(win) = 1/3
P(lose) = 2/3<br>
The probability of winning 3 and losing 2 in any particular order is {{{((1/3)^3)*((2/3)^2)}}}<br>
The number of different orders in which they can win 3 and lose 2 is C(5,3).<br>
So the probability that they win 3 of 5 matches is {{{C(5,3)*((1/3)^3)*((2/3)^2)}}}<br>