Question 1192295
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The center of the given circle is (3,5) and the radius is 4.<br>
The reflection in the line y=2 moves the center of the circle; the radius stays the same.<br>
The center of the circle is 3 units above the line of reflection, so the center of the new circle is 3 units below; the new center is (3,-1).<br>
The equation of the new circle is (x-3)^2+(y+1)^2=16.<br>
{{{(x-3)^2+(y+1)^2=16}}}
{{{x^2-6x+9+y^2+2y+1=16}}}
{{{x^2-6x+y^2+2y-6=0}}}<br>
B+D+F = (-6)+(2)+(-6) = -10<br>
ANSWER: -10<br>