Question 113156
To set up this word problem,it's good to start writing out what we know: 
We know George has two investments (let's call them x & y), one at 6% and the other at 8%.
The two investments yield a total of $185.60 in annual interest.
So, 0.06x+0.08y=185.60
Next: 
We know the amount invested at 8% is $320 less than twice the amount invested at 6% which means: y=2x-320. 
So that leaves us with: 0.06x+0.08y=185.60 and y=2x-320
Use the substitution method to continue solving. 

0.06x+0.08(2x-320)=185.60
0.06x+0.16x-25.60=185.60
0.22x=211.20
x=$960.00

0.06(960)+0.08y=185.60
57.60+0.08y=185.60
0.08y=128.00
y=$1600

Amt invested at 6%=$960.00
Amt invested at 8%=$1600.00