Question 1192229
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A plane slices a right circular cone parallel to its base at the midpoint of its height. 
The radius of the cone is 4 in. and its height is 12 in. Find the volume of the figure BELOW the plane. 
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The volume of the large cone is  {{{(1/3)*pi*r^2*h}}} = {{{(1/3)*pi*4^2*12}}} = {{{64*pi}}}  in^3.



The volume of the small (cut) cone is  {{{1/8}}}  of the volume ​of the large cone.


So, the cut volume is  {{{8pi}}}  in^3,  and the bottom part volume is  {{{64pi}}} - {{{8pi}}} = {{{56pi}}} in^3.    <U>ANSWER</U>
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Solved.