Question 1192176
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A Newton is a force on an object of mass *[tex \Large m] being acted upon by a gravitational acceleration of *[tex \Large g\text{ m/sec^2}].  1 Newton is *[tex \Large 1 \text{ kg\cdot m/sec^2}]. So an object of mass 9 kg that weighs 54 N, must be in a gravitational field with a net gravitational acceleration of *[tex \Large g] where *[tex \Large 9g\ = \ 54\text{ kg\cdot m/sec^2}], hence the net gravitational acceleration must be *[tex \Large 6\text{ m/sec^2}].  You should be able to get the rest by yourself.


Extra credit:  Is the mass of this fictional planet greater or smaller than Earth?


By the way, Ikleyn is absolutely correct.  My solution says basically the same thing except that I identify the constant of proportionality as the acceleration due to the local gravitational field.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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