Question 1192104
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If a formal algebraic solution is not required, here is a way to solve this kind of problem informally.<br>
(1) If all 374 tickets were child tickets, the total raised would be 374($3) = $1122; the actual total was $1524; the difference is $1524-$1122 = $402.<br>
(2) The cost of each adult ticket is $2 more than the cost of a child ticket.<br>
(3) The number of adult tickets was $402/$2 = 201.<br>
ANSWER 201 adults tickets; so 374-201 = 173 child tickets<br>
CHECK: 201(5)+173(3) = 1005+519 = 1524<br>