Question 1192062
{{{system(xy=-12,x+y=-1)}}}


{{{y=-x-1}}}
-
{{{x(-x-1)=-12}}}
{{{x(x+1)=12}}}
no real need to use other algebra from here.
two numbers differ by 1, product is 12
{{{3(4)=12}}}


But to get the negatives, numbers are 3 and -4.



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Note, Also For Factorization:
{{{-x^2-x=-12}}}
{{{x^2+x=12}}}
{{{x^2+x-12=0}}}
{{{(x-3)(x+4)=0}}}


x is 3 and the other number is -4.