Question 1192053
Cathy and Ernie had four consecutive even integers. They found that the product of the second and fourth was 16 less than the product of -3 and the sum of the first and third. What were their integers? 
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Use n-2, n, n+2 and n+4
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n*(n+4) + 16 = -3*((n-2)+(n+2))
n^2 + 4n + 16 = -6n
n^2 + 10n + 16  = 0
(n + 2)*(n + 8) = 0
n = -2 ----> -4, -2, 0, +2  (If zero is considered an even integer)
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n = -8 ----> -10, -8, -6, -4