Question 1191999
complex roots are conjugate
roots are +/-5i
1-3i, 1+3i
-3
Two factors are (x^2+25)(x+3)
The other two are (x+1+3i) (x-1-3i)
multiply those to get x^2-2x+10, which has roots (1/2)(2+/-sqrt(-36)) or (1/2) (2+/-6i)
=x^2-2x+10
a(x^2+25)(x+3)(x^2-2x+10) is the polynomial
when x=0 the value is 25*3*10=750, so a must be 2.
2(x^2+25)(x+3)(x^2-2x+10)
{{{graph(300,300,-10,10,-200,2000,2(x^2+25)(x+3)(x^2-2x+10))}}}