Question 1191988
18C11 are number of ways to choose 11 from 18=31,824
2C1*5C3*11C7 are ways to choose 1 wicket keeper, 3 bowlers, and 7 others from the 11 others=6600
2C1*5C4*11C6=4620
2C1*5C5*11C5=924
The number of ways is that sum, or 12,144