Question 1191959
<pre>
Cost equation for daily pass:  

    C_daily = 67x + 25x = 92x,  where x = # days skied


Cost equation for season pass:
    C_season = 350 + 25x

We wish to find x such that C_season < C_daily

   350 + 25x < 92x
       350   < 67x

       350/67 < x    
        5.224 < x     

    x = 6 ski days


Sanity check...


#days skied     Daily pass cost     Season pass cost
    4             368                   450
    5             460                   475
    6             552                   500    <----  Season pass becomes cheaper


If you plot the two cost equations, the point where they cross is the point where the season pass becomes more cost effective (well, the nearest integer above where they cross).   

The green line represents the season pass cost equation:

{{{ drawing(400,400, -10, 10, -50, 1000, grid(1),
             line (0,0,  9, 828), 
            green(line(0,350,9,575))
)
}}}