Question 1191964
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The sum of the measures of the interior angles of ANY *[tex \Large n]-gon is *[tex \Large (n\,-\,2)\cdot]180° .


The measure of an interior angle of a regular *[tex \Large n]-gon is the sum of the measures of the interior angles divided by *[tex \Large n].


The sum of measures of the exterior angles of ANY polygon is 360°.


The measure of each external angle of a regular *[tex \Large n]-gon is the sum of the measures of the external angles divided by *[tex \Large n].


Each point of a regular pentagram is an isosceles triangle, the base angles of which are supplementary to the interior angles of the central pentagon which you calculated above.  180° minus the sum of the two base angles gives you the measure of the acute vertex angle.


The measure of the reflex angles of a regular pentagram is 180° plus the sum of two base angles from the isosceles triangle that forms one of the points of the pentagram.


You can do your own arithmetic.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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