Question 1191933
Find the equation of the circle tangent to the line 5x + y = 3 at the point (2, -7) and the center is 
on the line x  -  2y = 19.
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Step 1, find the slope of the given line.
Step 2, find the equation of the perpendicular bisector of 5x + y = 3 thru the point (2,-7).
Step 3, find the intersection of the given line and the perpendicular bisector.
The intersection is the center of the circle at (h,k).
Step 4, find the distance from the center to the point (2,-7), that's the radius.
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{{{(x-h)^2 + (y-k)^2 = r^2}}} is the circle.
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