Question 1191934
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A line passes through A(-2, 1) and B(3, 4). 
(a) Find the point P on AB extended through B so that P is twice as far from A as from B. 
(b) the point Q on AB extended through B so that P is twice as far from B as from A.
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(a)  From A to B, there are 5 units along x-axis and 3 units along y-axis.


     Hence, to get point P, you should move 5 units along x-axis from B
                                        and 3 units along y-axis from B.


     Thus the destination point P is  P = (3+5,4+3) = (8,7).    <U>ANSWER</U>




(b)  Such point Q does not exist.


     (simply because AQ is always longer than BQ).
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Solved.