Question 1191833
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The answer from the other tutor is fine; however, with relatively small sets like this, there is an easier way to get to the answer.<br>
The set A ∩ B' consists of all the elements of A that are NOT in B.  So start with the set A and eliminate any elements that are also in B.<br>
q? no - also in B
s? no - also in B
u? yes -- not in B
w? yes -- not in B
y? no - also in B<br>
ANSWER: A ∩ B' = {u,w}<br>