Question 1191838
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We have three consonants M, G and C as three separate items and we have the block of two vowels AI as the fourth item.


There are 4! = 1*2*3*4 = 24 possible permutations of these four items,

and there are 2 permutations of the vowels A and I inside the block.


In all, it gives 2*4! = 2*24 = 48 possible different permutations/arrangements.     <U>ANSWER</U>
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Solved.