Question 1191792
Solve the equation:

x/(x+2) = (3x+1)/(x-1)  +4/(x^2+x-2)
Notice that x^2+x-2 = (x+2)*(x-1)
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x/(x+2) = (3x+1)/(x-1) + 4/(x+2)*(x-1)
Multiply thru by (x+2)*(x-1)
x*(x-1) = (3x+1)*(x+2) + 4
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x^2-x = 3x^2 + 7x + 2 + 4
2x^2 + 8x + 6 = 0
x^2 + 4x + 3 = 0
(x+3)*(x+1) = 0
x = -3, x = -1