Question 1191699
x = the amount invested at 11%.
y = the amount invested at 9%.


your equations are:


x + y = 140,000
.11x + .09y = 13,900


multiply both sides of the first equation by .11 and leave the second equation as it to get:


.11x + .11y = 15,400
.11x + 09y = 13,900


subtract the second equation from the first to get:


.02y = 1,500


solve for y to get:
y = 1,500 / .02 = 75,000


this means that x = 140,000 - 75,000 = 65,000.
this also means that .11 * x = .11 * 65,000 = 7,150.
this also means that .09 * y = .09 * 75,000 = 6,750.


total income is 7,150 + 6,750 = 13,900.
total invested is 65,000 + 75,000 = 140,000.


your solution is that 65,000 was invested at 11% and 75,000 was invested at 9%.


let me know if you have any questions or concerns.
theo