Question 1191678
given  {{{-2}}} and {{{3i }}}as roots

=>{{{-3i }}} is aso a root (This comes with conjugate pairs)

 the factors are: 
{{{(x-(-2))=x+2}}} 
{{{x-3i }}}
{{{x-(3i )=x+3i}}}

then

{{{f(x)=(x+2)(x-3i)(x+3i)}}}

{{{f(x)=x^3 + 2x^2 + 9x + 18}}}


{{{ graph( 600, 600, -10, 10, -50, 50, x^3 + 2x^2 + 9x + 18) }}}