Question 1191674
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If Mason had 1 coin, then the sample space is {H,T}
The sample space is the set of all possible outcomes.
H = heads
T = tails


If Mason had 2 coins, then the sample space is
{HH, TH, HT, TT}
Which I find easier to represent in the form of a two-way table like this
<table border = "1" cellpadding = "5"><tr><td></td><td>H</td><td>T</td></tr><tr><td>H</td><td>HH</td><td>HT</td></tr><tr><td>T</td><td>TH</td><td>TT</td></tr></table>
Not only is the table handy to organize all the items in the sample space, but it visually shows why multiplication is used to count all possible outcomes (2*2 = 4).


Let's calculate the probability of getting the outcome HH
That's as simple as noticing HH shows up 1 time out of 4 times total
Therefore,
P(HH) = 1/4


Or you could follow this pathway
P(H) = 1/2
P(HH) = P(H)*P(H)
P(HH) = (1/2)*(1/2)
P(HH) = 1/4
The second line is valid due to each coin flip being independent of one another.


If Mason plays 300 times, then he should expect to win 300*(1/4) = 300/4 = <font color=red>75 times</font>
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