Question 1191660
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{{{f(x) = 3x+2}}}
{{{f(5) = 3*5+2}}}
{{{f(5) = 17}}}


{{{g(x) = sqrt(x-1)}}}
{{{g(17) = sqrt(17-1)}}}
{{{g(17) = sqrt(16)}}}
{{{g(17) = 4}}}


Therefore,
{{{f(g(5)) = g(17) = 4}}}
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