Question 1191491
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If you have p consecutive integers and then you have the following p consecutive integers, then each integer in the second set is p more than the corresponding integer in the first set.<br>
So the difference between the sum of the p integers in the second set and the sum of the p integers in the first set is p times p, which is p squared.<br>
Give that that difference is 400, we have p^2=400 so p=20.<br>
ANSWER: 20<br>