Question 1191417
.
A bag contains seven red marbles and six blue marbles. 
Another bag contains six green marbles and eight yellow marbles. 
You randomly pick one marble from each bag. 
What is the probability that one marble is blue and one marble is yellow?
~~~~~~~~~~~~


<pre>
Blue marble comes from the first bag; yellow marbles comes from the second bag.


The probability under the problem's question is  


    P = {{{(6/(7+6))*(8/(6+8))}}} = {{{(6/13)*(8/14)}}} = {{{48/182}}} = {{{24/91}}}.    <U>ANSWER</U>
</pre>

Solved.