Question 1191360


 {{{x^2+y^2+12y=0 }}}  in polar form

Use the formulae that link Cartesian to Polar coordinates,


{{{x=r*cos(theta) }}} and{{{ y=r*sin(theta) }}}


 and substituting into the given equation



 {{{(r*cos(theta) )^2+(r*sin(theta) )^2+12r*sin(theta) =0 }}}


{{{r^2*cos^2(theta) +r^2*sin^2(theta) +12r*sin(theta) =0 }}}


{{{r^2(cos^2(theta) +sin^2(theta) )+12r*sin(theta) =0 }}}..........{{{cos^2(theta) +sin^2(theta)=1}}}


{{{r^2 + 12r*sin(theta) = 0}}}-> equation in polar form