Question 113007
{{{(3z-2)/-5<6}}} Start with the given inequality



{{{cross(-5)(3z-2)/cross(-5)>-5*6}}} Multiply both sides by -5 to get rid of the fraction. Note: when you multiply or divide both sides of an inequality by a negative number, the sign will flip.



{{{3z-2>-30}}} Multiply 



{{{3z+cross(-2+2)>-30+2}}} Add 2 to both sides



{{{3z>-28}}} Add



{{{cross(3/3)z>-28/3}}} Divide both sides by 3 to isolate z



So our answer is {{{z>-28/3}}}