Question 113002
let the {{{larger}}} number is {{{x}}} and the smaller number is {{{y}}} 

If the larger of two numbers is four times the smaller and their difference is six, then we have:

{{{x = (x-y)/4}}}

since their difference is {{{x-y = 6}}}, we have

{{{x = 6/4}}}

or

{{{x = 1.5}}}


so, the larger number is:{{{1.5}}}

and the smaller number is: {{{x-y = 6}}} => {{{x-6 = y}}} 

=> {{{y = 1.5 - 6 = -4.5}}} 

check:

{{{x = (x-y)/4}}}

{{{1.5 = (1.5-(-4.5))/4}}}

{{{1.5 = (1.5+4.5)/4}}}

{{{1.5 = 6/4}}}

{{{1.5 = 1.5}}}