Question 1191226
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C is least likely to win; so to avoid fractions...<br>
let x = probability that C wins
then 3x = probability that B wins  (3 times as likely as C)
then 6x probability that A wins  (twice as likely as B)<br>
The sum of the probabilities for all three horses is 10x; the probability that B or C wins is 4x.<br>
ANSWER: The probability that B or C wins is 4x/10x = 4/10 = 2/5 = 0.4 = 40%<br>