Question 112959
{{{(10x^4/3xy^2)/(6x^2*y/xy^4)}}}

when you divide rational numbers
always start with the operation between terms
here divide {{{10x^4/3xy^2}}} and/or {{{6x^2*y/xy^4}}}
 you can divide them at the same time
then we can get

{{{(10x^3/3y^2)/(6x/y^3)}}}

if the terms are in its simplest form

you divide them like dividing fractions

you take the reciprocal of the denominator and multiply it to the numerator

{{{(10x^3/3y^2)*(y^3/6x))}}}

divide the product of the numerators by the product of the denominators

{{{((10x^3)*(y^3))/((18x)*(y^2))}}}]

eliminate what you can eliminate to simplify

then we can get
{{{((5x^2)*(y))/9}}}