Question 112983
Let x be the smaller number
and (x+1) be the larger number

then we rewrite the problem as

{{{x+(x+1)=49}}}
combining like terms

{{{2x+1=49}}}
subtract 1 from both side of the equation we get

{{{2x=48}}}
divide both side by 2 and we get

{{{x=24}}}

therefore the two consecutive numbers are 24 and 25