Question 1191201
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How many different permutations can be formed from the letters in the word "essence"
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<pre>
The word has 7 letters; of them,  " e "  has the multiplicity 3 and  " s "  has multiplicity 2.


Therefore, the formula for the number of distinguishable permutations / (arrangements) is


    {{{7!/(3!*2!)}}} = {{{(7*6*5*4*3*2*1)/(1*2*3*1*2)}}} = 420.    <U>ANSWER</U>
</pre>

Solved.


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To see many other similar &nbsp;(and different) &nbsp;solved problems, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Arranging-elements-of-sets-containing-undistinguishable-elements.lesson>Arranging elements of sets containing indistinguishable elements</A> 

in this site.