Question 1191172

(a) two women and two men<pre>
(10 women CHOOSE 2)x(6 men CHOOSE 2)</pre>
(b) any mixture of men and women<pre>
(16 people CHOOSE 4)</pre>
(c) a majority of men<pre>
That's either (3 men and 1 woman) or (4 men)

(6 men CHOOSE 3)x(10 women CHOOSE 1) + (6 men CHOOSE 4)

You do the calculations.

Edwin</pre>