Question 1191120
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From the given conditions....<br>
P(A sends a message in a span of 6 minutes) = 6/16 = 3/8
P(A does not send a message in a span of 6 minutes) = 5/8
P(B sends a message in a span of 6 minutes) = 6/16 = 3/8
P(B does not send a message in a span of 6 minutes) = 5/8
P(C sends a message in a span of 6 minutes) = 6/14 = 3/7
P(A does not send a message in a span of 6 minutes) = 4/7<br>
Then....<br>
P(only A sends a message in a span of 6 minutes) = (3/8)(5/8)(4/7) = 60/448
P(only B sends a message in a span of 6 minutes) = (5/8)(3/8)(4/7) = 60/448
P(only C sends a message in a span of 6 minutes) = (5/8)(5/8)(3/7) = 75/448<br>
ANSWER #1: P(receiving only 1 message in a span of 6 minutes) = 195/448<br>
P(A and B send a message in a span of 6 minutes) = (3/8)(3/8)(4/7) = 36/448
P(A and C send a message in a span of 6 minutes) = (3/8)(5/8)(3/7) = 45/448
P(B and D send a message in a span of 6 minutes) = (5/8)(3/8)(3/7) = 45/448<br>
ANSWER #2: P(receiving two messages in a span of 6 minutes) = 126/448<br>
Simplify the fraction answers or convert to decimals or percentages as required/desired.<br>